python - open file named with two digit year-Python

Question

I'm opening a file named in the following format :

ex130626.log
exYYMMDD.log

following code wants 4-digit year. How to get the two digit year like 13?

today = datetime.date.today()
filename = 'ex{0}{1:02d}{2:02d}.log'.format(today.year, today.month, today.day)

Answer 1

年のモジュラスを取るだけです：

>>> import datetime
>>> today = datetime.date.today()
>>> filename = 'ex{:02}{:02}{:02}.log'.format(today.year%100, today.month, today.day)
>>> filename
'ex130625.log'

しかし、より簡単な方法はstrftime次のとおりです。

>>> today.strftime('ex%y%m%d.log')
'ex130625.log'

Answer 2

使用できますstrftime：

filename = 'ex' + today.strftime("%y%m%d") + '.log'

Answer 3

次のように最後の2つを取るだけです：

year = str(today.year)[-2:]
filename = 'ex{0}{1:02d}{2:02d}.log'.format(year, today.month, today.day)