php - Display if subarrays > 3 - PHP

Question

So I have a tv show website and I created custom lists where you can add whatever tv shows you want.

There is one table called lists (with user_id, list_title) and another table called show_lists which contains (list_id, show_id).

So my PHP is there:

     <?php
   $findlistsq = $conn->prepare('SELECT * FROM show_lists, shows, lists 
    WHERE lists.user_id = :user_id AND 
    lists.list_id = show_lists.list_id AND
    shows.id = show_lists.show_id');
   $findlistsq->execute(array(':user_id' => 2));
   $listscount = $findlistsq->rowCount();
         echo $listscount;
   $list = array();
   while ($listarray = $findlistsq->fetch()) {

    $list[$listarray['list_title']][$listarray['name']] = $listarray;

   }
   ?>    


   <?php
   foreach ($list as $key => $show) {
        echo $key; //echo title of list
       foreach ($show as $key => $value) {


        echo $value['name'];  //echo tv shows
     ;
    }
   }
   ?>

Basically, I create an array to join a list to its tv shows, display the title of the list and whatever it contains and so on. My question is: I want to display the list only if there is more than 3 shows (at least 3 different $value).

Can anybody tell me how I could do that ? Thanks!!

Edit: Also, there is slight chance that I might have overcomplicated this. Let me know if I did.