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関数 GetPivotedDataTable(data, "date", "id", "flag") が Pivoted 形式でデータを返しています。Task を使用してこのメ​​ソッドを呼び出したいのですが、Task で複数のパラメーターを渡す方法。

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5 に答える 5

0

「params」も使用できます。C#のパラメータ情報を確認してください

public class MyClass
{
    public static void UseParams(params int[] list)
    {
        for (int i = 0; i < list.Length; i++)
        {
            Console.Write(list[i] + " ");
        }
        Console.WriteLine();
    }

    public static void UseParams2(params object[] list)
    {
        for (int i = 0; i < list.Length; i++)
        {
            Console.Write(list[i] + " ");
        }
        Console.WriteLine();
    }

    static void Main()
    {
        // You can send a comma-separated list of arguments of the 
        // specified type.
        UseParams(1, 2, 3, 4);
        UseParams2(1, 'a', "test");

        // A params parameter accepts zero or more arguments.
        // The following calling statement displays only a blank line.
        UseParams2();

        // An array argument can be passed, as long as the array
        // type matches the parameter type of the method being called.
        int[] myIntArray = { 5, 6, 7, 8, 9 };
        UseParams(myIntArray);

        object[] myObjArray = { 2, 'b', "test", "again" };
        UseParams2(myObjArray);

        // The following call causes a compiler error because the object
        // array cannot be converted into an integer array.
        //UseParams(myObjArray);

        // The following call does not cause an error, but the entire 
        // integer array becomes the first element of the params array.
        UseParams2(myIntArray);
    }
}


/*
Output:
    1 2 3 4
    1 a test

    5 6 7 8 9
    2 b test again
    System.Int32[]
*/
于 2019-04-19T14:09:07.233 に答える