私は数千の値で NSString にコンマを挿入するメソッドを持っているアプリを持っています。今 1000 を入力すると、このメソッドを使用して 1,000 が表示されますが、1,000.00 が必要です。この問題。
- (NSString *)formatStringF:(NSString *)string {
// Strip out the commas that may already be here:
NSString *newString = [string stringByReplacingOccurrencesOfString:@"," withString:@""];
if ([newString length] == 0) {
return nil;
}
// Check for illegal characters
NSCharacterSet *disallowedCharacters = [[NSCharacterSet characterSetWithCharactersInString:@"0123456789."] invertedSet];
NSRange charRange = [newString rangeOfCharacterFromSet:disallowedCharacters];
if ( charRange.location != NSNotFound) {
return nil;
}
// Split the string into the integer and decimal portions
NSArray *numberArray = [newString componentsSeparatedByString:@"."];
if ([numberArray count] > 2) {
// There is more than one decimal point
return nil;
}
// Get the integer
NSString *integer = [numberArray objectAtIndex:0];
NSUInteger integerDigits = [integer length];
if (integerDigits == 0) {
return nil;
}
// Format the integer.
// You can do this by first converting to a number and then back to a string,
// but I would rather keep it as a string instead of doing the double conversion.
// If performance is critical, I would convert this to a C string to do the formatting.
NSMutableString *formattedString = [[NSMutableString alloc] init];
if (integerDigits < 4) {
[formattedString appendString:integer];
} else {
// integer is 4 or more digits
NSUInteger startingDigits = integerDigits % 3;
if (startingDigits == 0) {
startingDigits = 3;
}
[formattedString setString:[integer substringToIndex:startingDigits]];
for (NSUInteger index = startingDigits; index < integerDigits; index = index + 3) {
[formattedString appendFormat:@",%@", [integer substringWithRange:NSMakeRange(index, 3)]];
}
}
// Add the decimal portion if there
if ([numberArray count] == 2) {
[formattedString appendString:@"."];
NSString *decimal = [numberArray objectAtIndex:1];
if ([decimal length] > 0) {
[formattedString appendString:decimal];
}
}
return formattedString;
}