1

次の表を検討してください。

declare @table as table (
    GL_Group_Code   varchar(8),
    GL_Branch_Code  varchar(8),
    Account_Number  varchar(4),
    GL_Centre_Number    varchar(6)
)

insert into @table
select  '0100', '0110', '1200', 'S10118' union
select  '0100', '0110', '1580', 'S16053' union
select  '0200', '0210', '2050', '200049' union
select  '0200', '0210', '2050', '782844'

望ましい結果は、次の 4 つのソース列にわたる親子関係です。

declare @table_hier as table (
    Parent_ID   varchar(8),
    Item_ID     varchar(8)
)

列 1、2、3、4 の関係順序では、ソース テーブルの最初の行の結果は次のようになります。

null 0100
0100 0110
0110 1200
1200 S10118

2 行目は次のようになります。

null 0100
0100 0110
0110 1580
1580 S16053

関係の順序は、1、2、4、3、3、4、または 1、3、4 のように変化します。

私は再帰的なCTEを考えていますが、金曜日の後半にはほとんど助けがありませんでした。

4

2 に答える 2

0

このようなことを試してください

declare @table as table (
    GL_Group_Code   varchar(8),
    GL_Branch_Code  varchar(8),
    Account_Number  varchar(4),
    GL_Centre_Number    varchar(6)
)

insert into @table
select  '0100', '0110', '1200', 'S10118' union
select  '0100', '0110', '1580', 'S16053' union
select  '0200', '0210', '2050', '200049' union
select  '0200', '0210', '2050', '782844'

declare @table_hier as table (
    Parent_ID   varchar(8),
    Item_ID     varchar(8)
)

DECLARE @RelatonShip VARCHAR(4)

SET @RelatonShip = '134'

IF @RelatonShip = '1234'
BEGIN
    INSERT INTO @table_hier ( Parent_ID, Item_ID )
    SELECT GL_Group_Code, GL_Branch_Code FROM @table 
    UNION ALL SELECT GL_Branch_Code, Account_Number FROM @Table
    UNION ALL SELECT Account_Number, GL_Centre_Number FROM @table
END
IF @RelatonShip = '1243'
BEGIN
    INSERT INTO @table_hier ( Parent_ID, Item_ID )
    SELECT GL_Group_Code, GL_Branch_Code FROM @table 
    UNION ALL SELECT GL_Branch_Code, GL_Centre_Number FROM @Table
    UNION ALL SELECT GL_Centre_Number, Account_Number FROM @table
END
IF @RelatonShip = '34'
BEGIN
    INSERT INTO @table_hier ( Parent_ID, Item_ID )
    SELECT Account_Number, GL_Centre_Number FROM @table
END
IF @RelatonShip = '134'
BEGIN
    INSERT INTO @table_hier ( Parent_ID, Item_ID )
    SELECT GL_Group_Code, Account_Number FROM @table 
    UNION ALL SELECT Account_Number, GL_Centre_Number FROM @table
END

SELECT * FROM @table_hier
于 2013-09-21T13:09:52.400 に答える
0

テーブルに id があり、テーブル変数を使用して取得する列を格納できる場合は、次のことができます。

declare @ord table (id int)

insert into @ord
values (1), (2), (4)

;with cte as (
    select
        t.id,
        c.value,
        row_number() over(partition by t.id order by c.id) as rn
    from @table as t
        cross apply (
            values
                (1, t.GL_Group_Code),
                (2, t.GL_Branch_Code),
                (3, t.Account_Number),
                (4, t.GL_Centre_Number)
        ) as c(id, value)
    where
        exists (select * from @ord as o where o.id = c.id)
)
insert into @table_hier
select
    c1.value as Parent_ID, c2.value as Item_ID
from cte as c1
    inner join cte as c2 on c2.rn = c1.rn + 1 and c2.id = c1.id
order by c1.rn

insert into @table_hier
select null, t.Parent_ID
from @table_hier as t
where
    not exists
    (
         select *
         from @table_hier as t2
         where t2.Item_ID = t.Parent_ID
    )


select * from @table_hier

sql fiddle demo

または、データをテーブルまたは一時テーブルに保存できる場合は、動的 SQL ソリューションを使用できます。

declare @ord table (id int)
declare @stmt nvarchar(max)

insert into @ord
values (1), (2), (4)

;with cte as (
select c.name, row_number() over(order by c.colid) as rn
from sys.syscolumns as c
where
    c.id = object_id('dbo.table1') and
    exists (select * from @ord as o where o.id = c.colid)
)
select @stmt =
    isnull(@stmt + ', ', '') + 
    '(' + c1.name + ', ' + c2.name + ')'
from cte as c1
    inner join cte as c2 on c2.rn = c1.rn + 1
order by c1.rn

select @stmt = '
    insert into table_hier1
    select C.Parent_ID, C.Item_ID
    from table1 as t
        cross apply (
            values ' + @stmt + '
        ) as C(Parent_ID, Item_ID)
'

exec sp_executesql
    @stmt = @stmt

insert into table_hier1
select null, t.Parent_ID
from table_hier1 as t
where
    not exists
    (
         select *
         from table_hier1 as t2
          where t2.Item_ID = t.Parent_ID
    )

select * from table_hier1

sql fiddle demo

于 2013-09-21T13:46:49.433 に答える