0

この文字列を使用したいと思います:

probes <- c("BovineHD0500029561","BovineHD1100020616","BTB-00266062","BovineHD0200040828","BovineHD0100013622","BovineHD0100009413","BovineHD0300027356","BovineHD0600029053","BovineHD1500024004","BovineHD0200005954","BovineHD2900000062","BovineHD0200008162","BovineHD0400026684","BovineHD0200037832","BovineHD0300035509","Hapmap40156-BTA-103844","BovineHD0400022157")
chr <- c("chr5", "chr11", "chr12", "chr2", "chr1", "chr1", "chr3", "chr6", "chr15", "chr2", "chr29", "chr2", "chr4", "chr2", "chr3", "chr21", "chr4")

このループでは:

{
chr2 <- read.table("LRRadjustedall",chr,".txt", sep=";", header=TRUE)
probe <- c("probes")
pdf("boxplot""probes"".pdf")
boxplot(mat.num[,2], xlab="probes", ylab="LRR", main="probes")
}

つまり、上記のコマンドを 17 回繰り返します。最初のBovineHD0500029561==probesand chr5==chr... と最後のBovineHD0400022157==probesand chr4==chr.

何か提案はありますか?乾杯!

4

1 に答える 1