1

ここに私の現在のクエリがあります:

1

SELECT FilteredInvoice.accountidname, 
       FilteredInvoice.createdon, 
       FilteredInvoice.createdon AS sort_date, 
       FilteredInvoice.duedate, 
       FilteredInvoice.invoicenumber, 
       FilteredInvoice.statecodename, 
       FilteredInvoice.totalamount_base, 
       CONVERT(datetime, NULL) AS mag_paymentdate, 
       0 AS mag_amount_base, 
       GETDATE() AS Today
  FROM FilteredAccount AS CRMAF_FilteredAccount 
  JOIN FilteredInvoice ON FilteredInvoice.accountid = CRMAF_FilteredAccount.accountid 
  JOIN FilteredMag_Payment ON FilteredInvoice.invoiceid = FilteredMag_Payment.mag_invoiceid
 WHERE (FilteredInvoice.statecodename <> 'Canceled')

2

   SELECT FilteredInvoice_1.accountidname, 
          FilteredInvoice_1.createdon, 
          FilteredInvoice_1.createdon AS sort_date, 
          FilteredInvoice_1.duedate, 
          FilteredInvoice_1.invoicenumber, 
          FilteredInvoice_1.statecodename, 
          FilteredInvoice_1.totalamount_base, 
          FilteredMag_Payment.mag_paymentdate, 
          FilteredMag_Payment.mag_amount_base, 
          GETDATE() AS Today
     FROM FilteredAccount AS CRMAF_FilteredAccount 
LEFT JOIN FilteredInvoice AS FilteredInvoice_1 ON FilteredInvoice_1.accountid = CRMAF_FilteredAccount.accountid 
     JOIN FilteredMag_Payment ON FilteredInvoice_1.invoiceid = FilteredMag_Payment.mag_invoiceid
    WHERE (FilteredInvoice_1.statecodename <> 'Canceled')

これらだけで私が望んでいることを正確に実行しますが、「UNION」または「サブクエリ」を使用して結合しようとするとすぐに、2番目のクエリが壊れて間違った情報が表示されます。

私は金髪でこれを解決できないだけなのか、それとも実際に何か間違ったことをしているのだろうか.

すべての助けに感謝します。

サイモンに感謝します。

EDIT： 「間違った情報」とは、2番目のクエリが CRMAF_ プレフィックスをたどって実行されているアカウントからの値のみを返すのではなく、すべての値を返すことです。

4

2 に答える 2

2

「間違った情報」とはどういう意味かを推測するのは難しいですがUNION ALL、UNION.

UNION重複を削除するため、最初のクエリによって以前に返された場合、2 番目のクエリからのレコードは返されません。さらに、1 つのクエリ内での重複の可能性も排除されます。

のレコードUNION数は、2 つのクエリの合計レコード数よりも少なくなる場合があります。

2 つのレコードセットを連結するだけの場合は、次を使用しますUNION ALL。

SELECT FilteredInvoice.accountidname, 
       FilteredInvoice.createdon, 
       FilteredInvoice.createdon AS sort_date, 
       FilteredInvoice.duedate, 
       FilteredInvoice.invoicenumber, 
       FilteredInvoice.statecodename, 
       FilteredInvoice.totalamount_base, 
       CONVERT(datetime, NULL) AS mag_paymentdate, 
       0 AS mag_amount_base, 
       GETDATE() AS Today
  FROM FilteredAccount AS CRMAF_FilteredAccount 
  JOIN FilteredInvoice ON FilteredInvoice.accountid = CRMAF_FilteredAccount.accountid 
  JOIN FilteredMag_Payment ON FilteredInvoice.invoiceid = FilteredMag_Payment.mag_invoiceid
 WHERE (FilteredInvoice.statecodename <> 'Canceled')
UNION ALL
   SELECT FilteredInvoice_1.accountidname, 
          FilteredInvoice_1.createdon, 
          FilteredInvoice_1.createdon AS sort_date, 
          FilteredInvoice_1.duedate, 
          FilteredInvoice_1.invoicenumber, 
          FilteredInvoice_1.statecodename, 
          FilteredInvoice_1.totalamount_base, 
          FilteredMag_Payment.mag_paymentdate, 
          FilteredMag_Payment.mag_amount_base, 
          GETDATE() AS Today
     FROM FilteredAccount AS CRMAF_FilteredAccount 
LEFT JOIN FilteredInvoice AS FilteredInvoice_1 ON FilteredInvoice_1.accountid = CRMAF_FilteredAccount.accountid 
     JOIN FilteredMag_Payment ON FilteredInvoice_1.invoiceid = FilteredMag_Payment.mag_invoiceid
    WHERE (FilteredInvoice_1.statecodename <> 'Canceled')
于 2010-09-16T22:20:04.897 に答える
1

次のように、UNIONedクエリから得られるのと同じ結果を得ることができるはずです：

   SELECT FilteredInvoice_1.accountidname, 
          FilteredInvoice_1.createdon, 
          FilteredInvoice_1.createdon AS sort_date, 
          FilteredInvoice_1.duedate, 
          FilteredInvoice_1.invoicenumber, 
          FilteredInvoice_1.statecodename, 
          FilteredInvoice_1.totalamount_base, 
          CASE PF.pay_flag 
              WHEN 0.0 THEN CONVERT(datetime, NULL)
              ELSE FilteredMag_Payment.mag_paymentdate
          END AS mag_paymentdate, 
          FilteredMag_Payment.mag_amount_base * PF.pay_flag AS mag_amount_base, 
          GETDATE() AS Today
     FROM FilteredAccount AS CRMAF_FilteredAccount 
     CROSS JOIN (SELECT 1.0 pay_flag UNION SELECT 0.0) AS PF
     JOIN FilteredInvoice AS FilteredInvoice_1 ON FilteredInvoice_1.accountid = CRMAF_FilteredAccount.accountid 
     LEFT JOIN FilteredMag_Payment ON FilteredInvoice_1.invoiceid = FilteredMag_Payment.mag_invoiceid
    WHERE (FilteredInvoice_1.statecodename <> 'Canceled') AND
          (PF.pay_flag = 0 OR FilteredMag_Payment.mag_invoiceid IS NOT NULL)

編集: 左結合 FilteredMag_Payment

さらに編集: 最後の括弧で囲まれた OR 条件を WHERE 句に追加しました。

于 2010-09-17T13:00:54.330 に答える