c++ - stdout で freopen されたファイルの書き込みが速いのはなぜですか?

Question

Windows で実行すると、このテスト コードは次のようになります。

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <time.h>
#include <assert.h>

int main() {
    // The clock() function returns an approximation of processor time used by the program.
    // The  value  returned is the CPU time used so far as a clock_t;
    // to get the number of seconds used, divide by CLOCKS_PER_SEC.
    auto buf = new char[1048576]; // 1MB
    auto cache = new char[512 * 1024];

    // initialize the buffer
    for (int i = 0; i < 1048576; ++i)
        buf[i] = i;

    auto fp_reopen = freopen("data_freopen.bin", "wb", stdout);
    assert(fp_reopen != nullptr);
    setvbuf(fp_reopen, cache, _IOLBF, 512 * 1024);
    auto clock_begin = clock();
    for (int i = 0; i < 1000; ++i) {
        auto n = fwrite(buf, 1048576, 1, fp_reopen);
        assert(n == 1);
    }
    fflush(fp_reopen);
    auto clock_end = clock();

#ifdef _WIN32
    freopen("CONOUT$", "w", stdout);
#else
    freopen("/dev/tty", "w", stdout);
#endif

    printf("write with freopen clocks elapsed: %zu\n", clock_end - clock_begin);

    auto fp = fopen("data_fopen.bin", "wb");
    assert(fp != nullptr);
    setvbuf(fp, cache, _IOLBF, 512 * 1024);
    clock_begin = clock();
    for (int i = 0; i < 1000; ++i) {
        auto n = fwrite(buf, 1048576, 1, fp);
        assert(n == 1);
    }
    fflush(fp);
    clock_end = clock();
    fclose(fp);

    printf("write with fopen clocks elapsed: %zu\n", clock_end - clock_begin);
    delete[] buf;
    delete[] cache;
    getchar();
}

次の結果が生成されます。

• write with freopen clocks elapsed: 2767
• write with fopen clocks elapsed: 8337

なんで？